The examples below come from: RegentsPrep.org
Practice Problems:
In dealing with the occurrence of more than one event or activity, it is important to be able to quickly determine how many possible outcomes exist.

For example, if ice cream sundaes come in 5 flavors with 4 possible toppings, how many different sundaes can be made with one flavor of ice cream and one topping? 
Rather than list the entire sample space with all possible combinations of ice cream and toppings, we may simply multiply: 5 • 4 = 20 possible sundaes. This simple multiplication process is known as the Counting Principle.
The Fundamental Counting Principle: If there are a ways for one activity to occur, and b ways for a second activity to occur, then there are a • b ways for both to occur. 
Examples:
1. Activities: roll a die and flip a coin
There are 6 ways to roll a die and 2 ways to flip a coin.
There are 6 • 2 = 12 ways to roll a die and flip a coin.
2. Activities: draw two cards from a standard deck of 52 cards without replacing the cards
There are 52 ways to draw the first card.
There are 51 ways to draw the second card.
There are 52 • 51 = 2,652 ways to draw the two cards.
The Counting Principle also works for more than two activities.
3. Activities: a coin is tossed five times
There are 2 ways to flip each coin.
There are 2 • 2 • 2 • 2 •2 = 32 arrangements of heads and tails.
4. Activities: a die is rolled four times
There are 6 ways to roll each die.
There are 6 • 6 • 6 • 6 = 1,296 possible outcomes.

Probability describes the chance that an uncertain event will occur. 

Empirical Probability of an event is an “estimate” that the event will happen based on how often the event occurs after collecting data or running an experiment (in a large number of trials). It is based specifically on direct observations or experiences. Formula for probability of event E: 

Theoretical Probability of an event is the number of ways that the event can occur, divided by the total number of outcomes. It is finding the probability of events that come from a sample space of known equally likely outcomes. Formula for probability of event E (from sample space S): 

“AND” independent events A and B: “AND” dependent events A and B: P(A and B) = P(A)•P(B A) 
Complement of event A 
“OR” for not mutually exclusive events A and B: “OR” for mutually exclusiveevents A and B (no outcomes in common): also written 
Conditional probability of event Bgiven event A, for dependent eventsA and B: 
Remember to read carefully when dealing with dependent compound events
for references to “with replacement” or “without replacement.”
Here are some warmup examples:
(Decimal answers will be rounded to the nearest tenth, when needed.)
1. At a school fair, the spinner represented in the accompanying diagram is spun twice. What is the probability that it will land in section G the first time and then in section B the second time?Solution: The right angle tells us that sections R and G are each 1/4 of the entire circle, with section B being 1/2 of the circle. Answer: 

2. Shandra and Alexi roll two dice 50 times and record their results in the accompanying chart. a.) What is their empirical probability of rolling a 7? b.) What is the theoretical probability of rolling a 7? c.) How do the empirical and theoretical probabilities compare? 


Solution: a.) Empirical probability (experimental probability or observed probability) is 13/50 = 26%. b.) Theoretical probability (based upon what is possible when working with two dice) = 6/36 = 1/6 = 16.7% (check out the table at the right of possible sums when rolling two dice). c.) Shandra and Alexi rolled more 7’s than would be expected theoretically. 

3. The accompanying figure is a square. The interior sections are formed using congruent squares. If this figure is used as a dart board, what is the probability that the dart will hit the shaded blue region?Solution: The large square is broken into 9 smaller congruent squares of which 5 are shaded blue. The probability is 5/9 = 55.6%. 

4. Two colored dice (one red, one white) are rolled. a.) What is the probability of rolling “box cars” (two sixes)? b.) What is the probability of rolling “box cars” knowing the first toss is a six?Solution: a. The probability of getting “box cars” (two sixes) is (1/6)•(1/6) = 1/36. 


b. If, however, we roll the dice and see that the white die shows a six (and the red die is out of sight), the probability of the red die being six is 1/6. The probability of rolling “box cars”, knowing that the first roll is a six, is 1/6. The probability changes when you have partial information about the situation. This is a conditional probability situation.  
Solution: The complement of rolling “10 or less” is rolling 11 or 12. 